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Find the slope-intercept equation of the line with the following properties: Perpendicular to the line 푥 −8푦 = 8; containing the point (2,4).
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look who's here! what's up with the weird characters?
:O
haha wow the symbol wasn't meant to be there! It is a copy/past problem. Anyway it should say x - 8y
x-8y=8 -8y=8-x 8y=x-8 y=(1/8)x-1
M = 1/8 perpendicular M = -8 (inverse negative)
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Your line is: y-4=-8(x-2) y-4=-8x+16 y=-8x+20
so the final equation of y= -8+20 is the slope intercept form? I have not done this for a while and did not have time to read the chapter :'(
yea y=-8x+20 is slope intercept form
You're awesome! thanks :D
np
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