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Sin10/cos370 - tan10
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i can try to solve it
That'd be amazing!
\[\frac{ \sin10 }{ \cos370 }-\frac{ \sin10 }{ \cos10 }
i think u know cos370=cos(360+10)=cos10
then we can write\[\frac{ \sin10 }{ \cos370 }-\frac{ 10 }{ \cos10 }\]
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\[=\frac{ \sin10 }{ \cos10 }-\frac{ \sin10 }{ \cos10 }=0\]
Oh that makes sense thank you!
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