Sinx= 4/10 and secx<0 find exact value of cosx
have you learned about quadrant in trigonometry?
A little I know 2 and 3 are negative and 1 and 4 positive
Very perceptive. Now, in which quadrant does this angle lie?
Quadrant 4?
Why?
I don't know I was thinking either 1 or 4 because sin is positive
sin is not positive in quadrant 4
you're given that sin is positive.., and sec is negative.., remember that sec = 1/cos ..,
So it would be quadrant 2?
yes... :)
So how would I go about finding cosx?
|dw:1365665123001:dw| from the figure above.., can you label the side of right triangle given the value of sine x?
Opposite side would be 4 and the hypotenuse would be 10?
correct... :) now.., what side you should know to find cosine x?
Use pytherogeam to get 2 sq root 21 and then put adj over hyp and divide then I ended up with sq root 21/5
do you mean |dw:1365665610763:dw|
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