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Check my work please?
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Write \[ \log _{3} 6\] as a logarithm of base 2? The answer would be log base 2 of 6 over log base 2 of 3, right?
oh, okay, thanks!
I would double check that
I think you're correct @DeadShot wait..., what do you mean @Eyad ?
I checked it, it's log base 2of 6 over log base 2 of 3 according to my homework, because log6/log2 isn't a possible answer.
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Yeah I think you misread his question he has written to the base 3
Duh,@hea Your right I thought it was base to 2 not 3
then you are right !
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