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Mathematics 20 Online
OpenStudy (anonymous):

y = ax^2 + bx + c Determine the solution set of 0 = ax^2 + bx + c. is it {-2} ?

OpenStudy (compassionate):

\[ \begin{array}l\color{red}{\text{W}}\color{orange}{\text{E}}\color{#E6E600}{\text{L}}\color{green}{\text{C}}\color{blue}{\text{O}}\color{purple}{\text{M}}\color{purple}{\text{E}}\color{red}{\text{ }}\color{orange}{\text{T}}\color{#E6E600}{\text{O}}\color{green}{\text{ }}\color{blue}{\text{O}}\color{purple}{\text{P}}\color{purple}{\text{E}}\color{red}{\text{N}}\color{orange}{\text{S}}\color{#E6E600}{\text{T}}\color{green}{\text{U}}\color{blue}{\text{D}}\color{purple}{\text{Y}}\color{purple}{\text{!}}\color{red}{\text{!}}\color{orange}{\text{!}}\color{#E6E600}{\text{!}}\color{green}{\text{!}}\color{blue}{\text{!}}\color{purple}{\text{!}}\color{purple}{\text{!}}\color{red}{\text{!}}\color{orange}{\text{!}}\color{#E6E600}{\text{!}}\color{green}{\text{!}}\color{blue}{\text{!}}\color{purple}{\text{!}}\color{purple}{\text{!}}\color{red}{\text{}}\end{array} \]

OpenStudy (anonymous):

I I dont get it!

OpenStudy (anonymous):

this should answer your question http://en.wikipedia.org/wiki/Quadratic_equation happy reading

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

wait to thank me until you're sure you get it

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