Question

Which Value(s) of X are excluded from the solution to the following equation ? Show all of your work to get to your solution .

x^2-5x-20 x 2
----------------- = -------- + --------
x^2-17x+70 x-10 x-7

Answer 1

factorise the numerator and denominator

Answer 2

How do you do that ?

Answer 3

x
------ Would X = 10 ?
x-10

Answer 4

yep !

Answer 5

similarily for 2/x-7

Answer 6

at these points the fraction becomes undefined

Answer 7

So im going to have 3 diffrent answers ?

Answer 8

3? hwy 3 ?

Answer 9

Well Thats a NO ! But im still a little confused .
SO 2
------------- x= 9 ?
x-7

Answer 10

equate denominator to 0

x-7=0

x=?

Answer 11

how did u get a 0 ?

Answer 12

because denomiator cannot be 0 for a fraction

I considered that situation

Answer 13

oh okay . So x=7

Answer 14

yep :)

Answer 15

x^2-5x-20
---------------- = x = ??
x^2-17x+70

Answer 16

the conditions x=7,9 are to be excuded from answer..I think that answers ur question

Answer 17

I dont get it . Whats x ?

Answer 18

x=7 and 9 !

Answer 19

Oh okay . But i have to show work . And i dont know how u got that answer .

Answer 20

just by equation denomiators to 0

x-10 =0

x=10

x-7=0
x=7

oops its 10 not 9 :)

Answer 21

*equating

Answer 22

Okay but what about the first part of the problem.
x^2-5x-20
---------------- How do i find x here ?
x^2-17x+70

Answer 23

x^2-17x+70 factors to (x-7)(x-10) so you already have eliminated the x-values that don't work.