Question

Can anyone please explain how to solve and graph this inequality?

Answer 1

\[4y ^{2} \ge 36\]

Answer 2

This is what it looks like graphed. I use geogebra and its very helpful.

Answer 3

I can't seem to open the file :( can you explain please how to solve it... :(

Answer 4

Try opening this one.

Answer 5

Ok it opened... but how can I solve the equation? :(

Answer 6

Im not too good with this, but it could be x^2>=9

Answer 7

first, assuming this is a equation problem
so u have 4y^2 = 36
simplied, by divide 4 from both sides,
4/4y^2 = 36/4
y^2 = 9
subtract by 9 from both sides,
y^2 - 9 = 9 - 9
y^2 - 9 = 0
factor out, by using the difference squares formula :

a^2 - b^2 = (a+b)(a-b)

so, y^2 - 9 = 0
y^2 - 3^2 = 0
(y+3)(y-3) = 0
find the zeroes, make each factor be zero

y+3=0
subtract by 3 to both sides, giving us
y = -3

y-3=0
add by 3 to both sides,
y = 3

Answer 8

it doesnt clear yet :)

Answer 9

remember, this is inequality probem not equation problem.
make a number line to skecth where were interval for x's