Question

solve 3x=2x^2-2 by factoring

Answer 1

first transpose 3x to LHS
so it becomes
2x^2-3x-2=0
now it cn be represented as
2x^2-4x+x-2=0
group them
2x(x-2)+(x-2)=0
take x-2 as common
(x-2)(2x+1)=0
so x=2 x=-1/2