Question

using the discriminant, determine the number and type of solutions for this equation 5x^2-10x-2=0

Answer 1

\[5x^{2}-10x-2\]

Discriminant= \[b ^{2}-4ac\]
=\[(-10)^{2}- 4 (-2)(5)\]
\[=100+40=140\]

since the discriminant is positive
\[ \sqrt{D}=2\sqrt{35}\]
and it's not a perfect square
thus it will have 2 distinct Real roots.

hope u get it :-)