Question

solve by factoring.
2x^2-3x+1=0

Answer 1

2x^2-3x+1=0

(2x-1)(x-1) = 0

2x-1= 0 or x-1=0

I'll let you finish up

Answer 2

i cant finish up i dont understand factoring i tried i just dont get it.

Answer 3

from here, you solve each for x

2x-1= 0 or x-1=0

2x= 1 or x=1

x = 1/2 or x = 1

Answer 4

So the two solutions are x = 1/2 or x = 1

Answer 5

thank youu (:

Answer 6

yw