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The length of a rectangle is 5yd longer than its width. If the perimeter of the rectangle is 38yd, find its area.
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A=12
@BGrg007 your answer was wrong..
ahh sorry about that. that's the length. Area is 35 lol
wrong again @BGrg007
A = 84
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Let x = width of the rectangle x+5 = length of the rectangle Perimeter = 2(W) + 2(L) = 38 2(x) + 2(x+5) = 38 2x + 2x + 10 = 38 4x + 10 = 38 4x = 28 x= 7 yd Width x+5 = 12 yd Length Area = L*W = 12yd * 7 yd = ----------sq cm.
84 was right!
:D
2w+2(w+5)=38 2w+5=19 w=7 yd L=12 area=12 x 7=84 yd^2
i was doing it in my head. lol will use paper next time. sorry about the wrong info..twice *_*
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