Question

The length of a rectangle is three times its width.
If the area of the rectangle is 75in^2 , find its perimeter.

Answer 1

Let width of the rectangle is x
=> Length is 3x

Now Area = 3x.x = 3x^2

3x^2 = 75
=> x^2 = 75/3
=> x^2 = 25
=> x = +/- 5

But x = -5 is not possible because side can't be negetive.

hence, Width = 5
Length = 3 x 5 = 15

Perimeter = 2 (width + Length) = 2 (5 + 15) = 2 x 20 = 40

Answer 2

So, you know that length one is a, and length two is 3a. That means that the area of the square is 3a^2. Setting this equal to 75, we find that a is equal to sort(25) which is equal to five. Finding the perimiter is simple, as it is 3a + a + 3a + a = 8a = 40

Answer 3

i the peremiter 2 or 40?

Answer 4

Perimeter = 2 (width + Length) = 2 (5 + 15) = 2 x 20 = 40

Answer 5

if correct please click best response.

Answer 6

what is 15 x 5?