The length of a rectangle is four times its width.
If the perimeter of the rectangle is 70yd , find its area.

Question

The length of a rectangle is four times its width. 
If the perimeter of the rectangle is 70yd  , find its area.

anonymous · Answer

rectangle

formulas used

area  
perimeter

anonymous · Answer

this question is the same as the first one
2w+2(L+4)=70
2w+4=35
w=15.5yd
L=19.5
area=15.5 x 19.5= 302.25 yd^2

anonymous · Answer

@LilySwan your answer is wrong

anonymous · Answer

the answer was 196 yds squared.

anonymous · Answer

how we  solved the first one with the same formula you may try

anonymous · Answer

P= 2L +2W 
length is 4 x width
 L = 4 w 
W = W
P = 70

with this information you can begin solving

all you just need to do is plug in the information
 you should get and answer followed 
then you can use the area formula after finding length and width 
A=LW

anonymous · Answer

THE ANSWER WAS 196!

anonymous · Answer

im just telling you how to do this

anonymous · Answer

because if you verify  it by finding the perimeter again you will know that the found length and width are correct