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x-y=2 3x-3y=1
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Uh...\[3x - 3y = 1 \implies x - y =\dfrac{1}{3}\]But\[x - y = 2\]
x - y = 2 -->x = 2 + y now sub 2 + y in for x in the other equation 3x - 3y = 1 3(2 + y) - 3y = 1 6 + 3y - 3y = 1 3y - 3y = 7 0 = 7 There is no solution for this problem
oops...6 + 3y - 3y = 1 3y - 3y = 1 - 6 0 = - 5 still no solution :)
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