.When p = 3, a = 15, and a varies directly with p, match each value of p with the corresponding value of a.
TERM Definition
p=5 A) a=20
p=6 B) a=25
p=7 C) a=30
p=4 D) a=35
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jimthompson5910 (jim_thompson5910):
a = k*p
15 = k*3
15/3 = k
5 = k
k = 5
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So the equation is a = 5p
OpenStudy (anonymous):
...
jimthompson5910 (jim_thompson5910):
So for instance, when p = 5...
a = 5p
a = 5*5 ... plug in p = 5
a = 25
which means p = 5 matches to a = 25
jimthompson5910 (jim_thompson5910):
you do the same for the rest
OpenStudy (anonymous):
i still dont get it
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jimthompson5910 (jim_thompson5910):
when p = 6, what is 'a'?
jimthompson5910 (jim_thompson5910):
well plug it in
a = 5p
a = 5*6
a = ???
OpenStudy (anonymous):
i multiplied my answer with 5 :)
jimthompson5910 (jim_thompson5910):
to get ????
OpenStudy (anonymous):
what i did was 6*5 and got my answer
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jimthompson5910 (jim_thompson5910):
and you got what
OpenStudy (anonymous):
30
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
so p = 6 matches with a = 30
jimthompson5910 (jim_thompson5910):
and it sounds like you got the idea
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