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Algebra 10 Online
OpenStudy (anonymous):

I was wondering if someone can help me on a system of equations problem?

OpenStudy (anonymous):

OpenStudy (mertsj):

Did you solve the system?

OpenStudy (anonymous):

Let me check one second

OpenStudy (anonymous):

x = 26 y = 18

OpenStudy (mertsj):

And x is the ?

OpenStudy (mertsj):

ok. The problem say that x is the length and y is the width. So is the first choice true: The width is 12. Is that true?

OpenStudy (anonymous):

no?

OpenStudy (mertsj):

The problem said that the width is y. You got that y is 16. 16 is not 12. So the first one is false.

OpenStudy (anonymous):

I got y as 18 and okay

OpenStudy (mertsj):

The second one says the length is 36. Is that true?

OpenStudy (anonymous):

nope

OpenStudy (mertsj):

The third one says the width is 8 less than the length. Is 18 8 less than 26?

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

Then why don't you choose that answer?

OpenStudy (anonymous):

okay good idea thanks do you mind helping me on one more?

OpenStudy (mertsj):

If I can.

OpenStudy (anonymous):

I already got the answer of 600x^2y^3 but that isn't in the answer choices

OpenStudy (anonymous):

I'll be right back

OpenStudy (mertsj):

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