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An angle in the standard position of 201.8 degrees has a point P= (x,-2) on the terminal side. Find the value of x.
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@fprt Simply put \[\huge \tan\left(201.8^o\right)=\frac{y}{x}\]
So, transposing, so you the value of x \[\huge x=\frac{y}{\tan201.8^o}\]
hey thanks soo much! i think the answer i got is correct.
That's good :)
I have another question: Find a positive value in the equation 1+3cos pi/8(x+7)=0 How would I go about approaching this problem?
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@PeterPan
I don't get your question :(
Well i dont understand the question either, it is question 4 in the attached file
I really do not understand :(
oh ok thanks for your help
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