Question

An angle in the standard position of 201.8 degrees has a point P= (x,-2) on the terminal side. Find the value of x.

Answer 1

@fprt
Simply put
\[\huge \tan\left(201.8^o\right)=\frac{y}{x}\]

Answer 2

So, transposing, so you the value of x
\[\huge x=\frac{y}{\tan201.8^o}\]

Answer 3

hey thanks soo much! i think the answer i got is correct.

Answer 4

That's good :)

Answer 5

I have another question: Find a positive value in the equation 1+3cos pi/8(x+7)=0 How would I go about approaching this problem?

Answer 6

@PeterPan

Answer 7

I don't get your question :(

Answer 8

Well i dont understand the question either, it is question 4 in the attached file

Answer 9

I really do not understand :(

Answer 10

oh ok thanks for your help