Question

a pendulum bob of mass m/2 carrying a charge 2q is at rest with its string making an angle theta with the vertical in uniform horizontal electric field E. the tension on the string is

Answer 1

(m/2)gcos(theta) + E(2q)sin(theta)

Answer 2

tension:\[T=(m/2)g/\cos \theta=2qE/\sin\]

Answer 3

\[T =\sqrt{\left( mg/2 \right)^{2}+(2qE)^{2}}\]