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Find the arc length of the curve x = 8et cos 6t, y = 8et sin 6t where 0 ≤ t ≤ π/2.
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i got my dx/dt to be \[-48e ^{t}\sin(6t) +8e ^{t}\cos(6t)\]
and i got my dy/dt to be \[48e ^{t}\cos(6t) +8e ^{t}\sin(6t)\]
-48etsin6t+48etcos6t
what's that for?
what are you getting for your derivatives or your g'(x) and f'(x)?
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derivative of x -48etsin6t
derivative of y 48etcos6t
what about the product rule?
:D sorry
lol np
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