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what are the real number solutions of the equation x^4+2x^3-4x^2=0?
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Factor out x^2
x^2(x^2+2x-4)
Now set each factor equal to 0 and solve.
how would you factor x^2+2x-4
It won't factor. Use the quadratic formula.
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" well are you going to draw your weapons, or are you going to whistle Trixie ? "
The sign of the discriminant determines the number of solutions if positive : 2 real solutions if zero : 1 real solutions
@Luis_Rivera How does that tell what the solutions are?
it doesnt !
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