Question

Write the following expression as a sum and/or difference of logarithms. express power as factors.
log(base d) (u^2 v^5) u>0, v>0

Answer 1

\(\log_du^2v^5=\log_du^2+\log_dv^5=2\log_du+5\log_dv\)

Answer 2

wow now that I see it done doesn't look that scary. then what does the u>0 and v>0 play in the equation?

Answer 3

they tell us that because neither u nor v can equal 0, else the equation would be undefined because log(0) does not have an answer

Answer 4

okay thank you!

Answer 5

of course :)