There are 5 people in a room. Make the following simplifying assumptions about their birthdays: Ignore leap years; assume 365 days in the year. For each person, assume that the chance he/she is born on a specified day is 1/365. No twins! Assume that the chance that someone is born on a specified day is not affected by other people’s birthdays.

Question

There are 5 people in a room. Make the following simplifying assumptions about their birthdays:  Ignore leap years; assume 365 days in the year. For each person, assume that the chance he/she is born on a specified day is 1/365. No twins! Assume that the chance that someone is born on a specified day is not affected by other people’s birthdays.

mertsj · Answer

Is there a question here somewhere?

anonymous · Answer

yes they are cheating at Stat2.2x (edx.org)

anonymous · Answer

Find the chance that the 5 people have 5 different birthdays.

anonymous · Answer

can any one ans

anonymous · Answer

An urn contains 10 white balls and 5 blue balls. Draws are made repeatedly from the urn as follows. On each draw, a ball is drawn and its color noted; then it is replaced in the urn along with 3 more balls of its color.

PROBLEM 4A

Find the chance that the first ball drawn is blue.