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Algebra
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Bewler, could you Explain how you would find the vertex for y = 2x2 – 5x – 3. Also, explain how you would graph this quadratic function.
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y=a\[x^{2}\]+bx+c -b/2a is a k vertexs x axis f(k)= y axis .....vertex(k,y)
-b/2a=-5/4
what?
let vertex = (r,k) r=-b/2a k=f(r)
|dw:1365958440982:dw|
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|dw:1365958547690:dw|
y=2x^2-5x-3 r=5/2(2) ?
yes:)
k=f(5/4)
what does the f stand for
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functon of y wait ı will show
like the f(x) thing?
|dw:1365958863196:dw|
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