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Algebra 21 Online
OpenStudy (anonymous):

Bewler, could you Explain how you would find the vertex for y = 2x2 – 5x – 3. Also, explain how you would graph this quadratic function.

OpenStudy (anonymous):

y=a\[x^{2}\]+bx+c -b/2a is a k vertexs x axis f(k)= y axis .....vertex(k,y)

OpenStudy (anonymous):

-b/2a=-5/4

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

let vertex = (r,k) r=-b/2a k=f(r)

OpenStudy (anonymous):

|dw:1365958440982:dw|

OpenStudy (anonymous):

|dw:1365958547690:dw|

OpenStudy (anonymous):

y=2x^2-5x-3 r=5/2(2) ?

OpenStudy (anonymous):

yes:)

OpenStudy (anonymous):

k=f(5/4)

OpenStudy (anonymous):

what does the f stand for

OpenStudy (anonymous):

functon of y wait ı will show

OpenStudy (anonymous):

like the f(x) thing?

OpenStudy (anonymous):

|dw:1365958863196:dw|

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