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Could someone check my work? Solve (x + 3)^2 = 36 for x
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√(x+3)^2 = √36 x+3 = 6 -3 -3 x=6
when you take the square root of both sides, you will have a plus/minus
for example x^2 = 1 x = +-sqrt(1) x = 1 or x = -1
x=3
so your step 2 should be x+3 = 6 or x+3 = -6
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so 3 and -9
Ok, got cha
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