Question

a car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105m. whats acceleration? help

Answer 1

\[a=\Delta v/\Delta t\]

Answer 2

\[a=v_1-v_0/t_1-t_0\]

Answer 3

v initial = -22.7

v final = -10.9

not this

Answer 4

\[v ^{2}= u ^{2} + 2as\]

Answer 5

v initial and final above

displacement 105 meters in the negative direction which is -105m

Answer 6

\[(-10.9)^{2}=(-22.7)^{2} + 2a(-105)\]

Answer 7

solve for a

Answer 8

-6.104?

Answer 9

the minus sign simply means he is decelerating

Answer 10

yw

Answer 11

thank u

Answer 12

double check your math i did not COMPUTE IT

Answer 13

yw