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OpenStudy (anonymous):
2x^3-12x^2+ 18x-108/x-6
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OpenStudy (anonymous):
A. 4x2 + 9x B. 2x2 + 18 C. 3x + 5 D. 3x + 2
OpenStudy (anonymous):
$$\frac{2x^3-12x^2+18x-108}{x-6}=\frac{2x^2(x-6)+18(x-6)}{x-6}=\frac{(2x^2+18)(x-6)}{x-6}$$
OpenStudy (anonymous):
it is b?
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