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Find the area between the graph of y=x^2-2 and the x-axis, between x=0 and x=6.
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\[\int\limits_{0}^{6}x^2-2\]
I need to find the area above and below the x axis though and i'm not sure how to do that
Do you know what the graph looks like?
it's a parabola
|dw:1366065132749:dw| \[\int\limits_{0}^{\sqrt{2}}(x^2-2)dx+\int\limits_{\sqrt{2}}^{6}(x^2-2)dx\]
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