Question

how to solve sin^2phetacospheta=2sin^3pheta

Answer 1

is this pheta or theta???

Answer 2

is ur question this?
\(\sin^2\theta\cos\theta=2\sin^3\theta\)
@amina.kalla

Answer 3

Let pheta = x.

Then, assuming the equation is as written above by @ajprincess , we get:

(sin² x) (cos x) = 2 sin³ x

(sin² x) (cos x) - 2 sin³ x = 0

Factor out (sin² x) to get:

(sin² x) [ cos x - 2 sin x ] = 0

Use the Zero Product Property to write:

(sin² x) = 0 or [ cos x - 2 sin x ] = 0

@amina.kalla Your task is to solve the two equations directly above.

Answer 4

thnks

Answer 5

Did you get it solved? @amina.kalla

Answer 6

can u help me with this quest cos(theta)=sin(theta/2)

Answer 7

I will need to look up the half angle formula for sine.

Answer 8

cos(3theta)

Answer 9

=sin(theta/2)

Answer 10

I thought this is the question: cos(theta)=sin(theta/2)

Answer 11

the quest is cos (3theta)

Answer 12

@amina.kalla I don't know how to solve that trig equation now.

Answer 13

so the question is \(\cos3\theta=\sin(\theta/2)\). right?

Answer 14

yes

Answer 15

\(\sin(\theta/2)=\cos(\pi-(\theta/2))\)
so
\(\cos3\theta=\cos(\pi-(\theta/2))\)
\(3\theta=\pi-(\theta/2)\)
nw can u find \(\theta\)?

Answer 16

ok thnks

Answer 17

welcome:)