what are the factors of 3x2– 33x + 84
3(x-7)(x-4)
would you like to know how to do it?
yes plz
Have you heard of FOIL before? First terms, Outer terms, Inner terms, Last terms
ya
cool, then you know that's how you times out the factors to get the equation, so essentially we're doing the opposite: so first you look at the equation as:
\[ax ^{2}+ bx +c\]
in our case: a = 3 b = -33 c= 84 so... what are the factors of our "a" term? (3)
basically: what times what = 3?
1*3
perfect, so our factors for a will be 3 and 1 so it's starting to look like: (3x + __ ) (1x + __ )
next, "c" = Last term times Last term in our case c = 84 so what times what = 84?
1,84 2,42 3,28 4,21, 6,14 7,12
we cant pick it yet, so we work our the b term's factors these factors will add to equal -33 and multiply to equal 84 remember from foil though that it's Outer terms + Inner terms will equal b (so don't forget the 3x)
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