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OpenStudy (anonymous):
The graph of y = ax2 + bx + c is a parabola that opens up and has a vertex at (0, 5). What is the solution set of the related equation 0 = ax2 + bx + c?
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OpenStudy (anonymous):
@triston69 ı can solve
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
vertex ( r,k) = (0,5) a.(x-r)^2+k =y so a.x^2+5 =y = 0 a.x^2= -5 but parabol is open upward so a is not negative and x^2 is not negative so a.x^2 can not equal to -5 and no solution
OpenStudy (anonymous):
|dw:1366036872768:dw|
OpenStudy (anonymous):
thx
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OpenStudy (anonymous):
welcome
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