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If n is an even number, which statement is true about n + 1? A) It is a prime number. Eliminate B) It is an even number. C) It is an odd number. D) It is a perfect square.
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C, guessing. N=even, adding one should make it odd.
If \(n\) is even, it is expressible as \(2k\) for some \(k\in\mathbb{N}\). Adding one yields \(2k+1\), which is not divisible by \(2\) and is therefore *odd*.
thanks @ClawTalon and @oldrin.bataku .. :]
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