Question

solve over domain -3pi/2 greater or equal to x < pi/2 for (cos2x)(cosx) - (sin2x)(sinx) = 0

Answer 1

divide by cosx althrought what do we have

Answer 2

\[\cos2x-\sin2xtanx=0\]

Answer 3

cos 3x = 0

Answer 4

\[\cos2x-2sinxcosx.sinx/cosx\]

Answer 5

\[\cos2x-2\sin ^{2}x=0\]

Answer 6

\[\cos ^{2}x-\sin ^{2}x-2\sin ^{2}x=0\]

Answer 7

cos (alpha + beta) trig identities

Answer 8

not so comfortable with that refer you to @inyourhead

Answer 9

I don't do math buddy.

Answer 10

cool @inyourhead that was the only name i can spell out

so i havent met you on any Qs what is up