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Mathematics 8 Online
OpenStudy (anonymous):

Hi! Everybody back again with another headache. Can anybody help me find the domain and range for h(x)=1/(1- sin x)

OpenStudy (anonymous):

the function is valid for every \[\sin x \neq 1\] so, the domain is: R-{(2n+1)*pi/2}

OpenStudy (anonymous):

clearly, sin x varies from -1 to 1 so, h(x) can take values between 1/2 and +infinity range: \[(1/2 , \infty)\]

OpenStudy (anonymous):

thanx man

OpenStudy (anonymous):

welcome :)

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