1. What is the equation of the circle with the given graph?

(Points : 5)
(x + 3)2 + (y 2)2 = 2

(x 3)2 + (y + 2)2 = 2

(x + 3)2 + (y 2)2 = 4

(x 3)2 + (y + 2)2 = 4

Question

1. What is the equation of the circle with the given graph?

(Points : 5)
       (x + 3)2 + (y  2)2 = 2

       (x  3)2 + (y + 2)2 = 2

       (x + 3)2 + (y  2)2 = 4

       (x  3)2 + (y + 2)2 = 4

anonymous · Answer

attachment

jim_thompson5910 · Answer

Hint:

the center of this circle is (3, -2)

the radius is r = 2

jim_thompson5910 · Answer

The general equation of a circle is 

(x-h)^2+(y-k)^2=r^2

where

center: (h,k)

radius:  r

anonymous · Answer

so it would be the last one?

jim_thompson5910 · Answer

yep

anonymous · Answer

thank you can you check some more of my answers plz?

anonymous · Answer

thank you anyway :) and thanx for the medal :)

jim_thompson5910 · Answer

sure, but just a few more though and you're welcome

anonymous · Answer

okay I posted them in a diffrent post

anonymous · Answer

http://openstudy.com/study#/updates/516c6bb5e4b063fcbbbc853a