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3/4x + 1 = -8 x=
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\[\frac{ 3 }{ 4x }+1=8\]\[\frac{ 3 }{ 4x }=8-1\]\[\frac{ 3 }{ 4x }=7\]\[3=7(4x)\]\[7(4x)=3\]\[28x=3\]\[\frac{ 28x }{ 28 }=\frac{ 3 }{ 28 }\]\[x=\frac{ 3 }{ 28 }\]
sorry but im only solving for x in the equation
did i just give the x? O_O
i dont think so love
\[\frac{ 3 }{ 4x }=-9\]\[-9(4x)=3\]\[x=-\frac{ 1 }{ 12 }\]I made a mistake. so that's the x
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