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OpenStudy (anonymous):
Suppose a population of 50 crickets doubles in size every 4 months. How many crickets will there be after 5 years?
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OpenStudy (anonymous):
125
OpenStudy (jim766):
y = 50(2)^15 =
OpenStudy (jim766):
50 is what you start with, 2 is how much the amount it multiplied 15 is the number of 4 month periods in 5 years. y = a(b)^x
OpenStudy (jim766):
much bigger than 125,,,
OpenStudy (anonymous):
oh i sorry i miss read years for months
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