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Suppose a population of 50 crickets doubles in size every 4 months. How many crickets will there be after 5 years?
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125
y = 50(2)^15 =
50 is what you start with, 2 is how much the amount it multiplied 15 is the number of 4 month periods in 5 years. y = a(b)^x
much bigger than 125,,,
oh i sorry i miss read years for months
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