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Simplify: (x^2 - 9)/(x^3 - 3x^2)
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factor the numerator ,the top factor the denominator, the bottom any idea how to start?
I know how to do it but could you answer it since this one just confuses me
x^2-9 is a difference of 2 squares do you know how that factors?
\[\frac{x^2-9}{x^3 -3x^2} \\ \frac{ ( x-3)(x+3)}{x^2( x -3)}\\ \frac{ ( x+3)}{x^2}\\\]
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