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find the exact value, in radians, of the expression tan-1(-square root 3)
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\[\text{ArcTan}\left[-\sqrt{3}\right]=-\frac{\pi }{3} \]
how did you get to that answer?
It is the special right triangle where the acute angles are 30 and 60 degrees. pi/3 is 60 degrees.
wow thank you soo much
|dw:1366072950212:dw|
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@Kiara_Wright10 Sorry. My bad. The idea was correct, the drawing was incorrect. Refer to the revised drawing above.
thank you
You're welcome.
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