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Simplify the expression: 6x^2+7x-3 / 4x^2-9
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(2x+3)(3x-1)/(2x+3)(2x-3) = (3x-1)/(2x-3)
\[\frac{ 6x^2+7x-3 }{ 4x^2-9 }\] Factor out common multiples \[\frac{ (3x-1)(2x+3) }{ (2x+3)(2x-3) }\] Then simplify
So the final answer should be \[\frac{ 3x-1 }{ 2x-3 }\]
and thats what i meant sorry
Oh wow. Thanks Ya'll!!!
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Same as physic said just in equation form :P
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