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14t^2-9t+1 factor
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u get two factors x=1/2 and x= 1/7
http://0.tqn.com/d/create/1/0/i/9/9/-/Quadratic.formula.jpg u use this formula
and u get \[(-9 \pm \sqrt{25})/28\]
then u simplify and u get x=9+5/28 and x= 9-5/28 and then u get the factors
oh and u take a= 14 b=-9 and c=1 by comparing with ax^2+bx+c
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