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How do I solve logv12 (x + 1) - logv12 4 = logv12 16?
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\[\log_{12} (x+1) - \log_{12} 4=\log_{12} 16\]
Solve log12 (x + 1) – log12 4 = log12 16 log12 ((x+1)/4) = log12 16 ((x+1)/4) = 16 (x+1) = 64 x=63
Is there any more? @DeadShot ?
No, that's all of them, thanks for the help!
Fan me if you think you will have more.
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*later on*
I did, I might have more in a little while.
Ok. np.
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