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\[\frac{ (k+2)(4k-2)(3k+2) }{ 4k-2}\]
\[(k+3)(3k+2)\]
\[\frac{ x ^{2}-4 }{ (x-8)(x-2) }\]
\[\frac{ (x-2)(x+2) }{ (x-2)(x-8) }\]
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\[\frac{ x+2 }{ x-8 }\]
did you get it @123baby
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