Question

aascsC

Answer 1

question?

Answer 2

For the first one: you want to get common denominators for all three fractions.

Answer 3

The common denominator should be 6x, so you will do this:

10 • 2 4 • 2x (7 + x) • 3
-- + -- = ------
3x • 2 3 • 2x 2x • 3

Answer 4

Then simplify:

20 8x 21 + 3x
-- + -- = -------
6x 6x 6x

Answer 5

This can be simplified even further:

20 + 8x 21 + 3x
------- = -------
6x 6x

Answer 6

These are the steps...

Answer 7

i am solving on paper first...

Answer 8

Then you forget about the denominator for now and solve for numerators:

20 + 8x = 21 + 3x
-20 -20
----------------
8x = 1 + 3x
-3x -3x
---------------
5x = 1

5x 1
-- = --
5 5


x = ?

Answer 9

if you look at the last step, the answer is in there..
5x ÷ 5 = x
and you also divide 1 by 5 and that would be your answer...

Answer 10

yes :)

Answer 11

i am trying to solve it..

Answer 12

For #10:
cross multiply (x+12 • x+8 & x+4 • x):

(x + 12)(x + 8) = x(x + 4)

Answer 13

Next,

simplify (x + 12)(x + 8). You would multiply the each term in the first set of parentheses by each term in the second parentheses:

x^2 + 8x + 12x + 96 = x^2 + 4x

Answer 14

Do you understand this so far? :)

Answer 15

x^2 + 8x + 12x + 96 = x^2 + 4x
x^2 + 20x + 96 = x^2 + 4x


x^2 + 20x + 96 = x^2 + 4x
-x^2 -x^2
------------------------
20x + 96 = 4x


20x + 96 = 4x
-20x -20x
-----------------
96 = -16x


96 -16x
--- = ----
–16 -16

x = –?

Answer 16

not quite.. you have to divide 96 by -16 to get value for x

Answer 17

correct! :)