Question

Please help me!!!!
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.

(tan(X)+tan(y))/1-tan(x)tan(y)=cot(x)+cot(y)/cot(x)cot(y)-1

Answer 1

the left side of the equation is

\[\tan(x + y)\]

the right hand side is

\[\frac{1}{\cot(x + y)} = \frac{\cot(x)+\cot(y)}{\cos(x)\cot(y) -1}\]

so 1/cot = tan

therefore left hand side = right hand side