Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

y = two thirdsx − 10

y = two thirdsx + 10

y = −three halvesx − 10

y = −three halvesx + 10

Question

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

y = two thirdsx − 10

y = two thirdsx + 10

y = −three halvesx − 10

y = −three halvesx + 10

anonymous · Answer

http://www.mathportal.org/calculators/analytic-geometry/parallel-and-perpendicular-calculator.php

anonymous · Answer

$$2x - 3y = 3$$
$$2x - 3 = 3y$$
$$y = \frac{ 2x - 3 }{ 3 }$$
$$m = \frac{ 2 }{ 3 }$$
$$m = -\frac{ 3 }{ 2 }$$
---------------------
$$y - 2 = -\frac{ 3 }{ 2 } (x + 8)$$
$$2y - 4 = -3x - 24$$
$$y = \frac{ -3x - 20 }{ 2 }$$
$$y = -\frac{ 3 }{ 2 }x - 10$$