if the complex number Z lies on the circle |Z-2i| = 2sqrt(2) then find arg( (Z-2)/Z+2) ) ?

Question

if the complex number Z lies on the circle |Z-2i| = 2sqrt(2) then find  arg( (Z-2)/Z+2) ) ?

anonymous · Answer

@shubhamsrg  @siddhantsharan  @electrokid @satellite73  @RadEn @ash2326

anonymous · Answer

wasnt this answered earlier today?

anonymous · Answer

Yes..But it wanst Convincing For me..

anonymous · Answer

what do you mean "convincing"?
you can have proofs in many ways.. the previous solution was very interpretive and nice.
and a valid mathematical proof.

anonymous · Answer

i mean..i cant follow their Solutions..

anonymous · Answer

just because the proof was short doesnt meant that aint right! infact, thats what is expected. the shortest way to proove something

anonymous · Answer

Yeah....But i dont Understand How they did it..

anonymous · Answer

Refer to Phi's drawing at http://openstudy.com/users/yahoo!#/updates/516e916ee4b09b9167f12416 do you agree with the drawing there?

anonymous · Answer

Lol...i cant see his drawing?