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Chemistry 13 Online
OpenStudy (e.cociuba):

How many moles of sodium nitrate are in 0.85 of a 0.28 M NaNO3 solution? a.) 0.24 mol b.) 0.33 mol c.) 3.1 mol d.) 0.87 mol

OpenStudy (e.cociuba):

I divided 0.28 M/ 0.85 = .329, which is b.) Is tht correct?

OpenStudy (e.cociuba):

|dw:1366237015488:dw| Is tht correct @Anonymous1921

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