Question

Please help. In △PQR, QS is an altitude.

Solve for x and y.
The problem and the choices are attached below.

Answer 1

Can anyone please help me with this one?

Answer 2

I have 4 choices for answers, they are

Answer 3

\[ \frac{3}{x}= \frac{x}{27}\\\\x^2 = 81\\y= \sqrt{810 }\\ x= 9 \]

Answer 4

\[ \frac{27 + 3}{y}= \frac{y}{27}\\\\ \frac{30}{y}= \frac{y}{27}\\\\y^2 = 810\\\\ y= \sqrt{810 }\\\\ y= 9\sqrt{10 }\]

Answer 5

Thank you so very much, sorry for the slow response I got kicked off the internet.