Question

please help explain how to solve this on the unit circle. interval (0, 2pi) for (sinx -1)(2sin^2x-5 sinx+2)=0

Answer 1

Try using the 0-product property.

Answer 2

I'm not sure what that is

Answer 3

Remember in algebra when there was an equation like (x-1)(x-2)=0?

Answer 4

how do I solve it on the unit circle

Answer 5

Not exactly. The property is that if there is a multiplication that equals 0, then one or more factors must equal 0.

Answer 6

i dont remember that. can you please explain further

Answer 7

So for (x-1)(x-2)=0, then either x = 1 or x=2.
That's how I would solve it.

Answer 8

would x= 2pi,x=pi/2, x=5pi/4 be right?

Answer 9

Try plugging it into the equation.