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x + (x+5) + (x-1) + x + (x+8) => 5x + 12
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Start out by removing parentheses. You get a bunch of x-terms and a bunch of constants. Now combine like terms. What do you get on the left side?
20x?
No. Remember that only other terms with x's in them can combine with terms with x's in them.\[x + x + 5 + x - 1 + x + x + 8 = 5x + 12\]
Do you understand how I got 5x + 12?
no
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First I combined all the x terms. There are five x-terms. That makes 5 times x, or 5x.
And then there are a bunch of random numbers, which are 5, -1, and 8, so I add them up to get 12. So it's 5x + 12.
Do you understand?
5x + 12 is in the problem
x +x + 5 + x - 1 + x + x + 8 => 5x + 12 This is an inequality...correct ?
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